x^2+20x-2600=0

Solution for x^2+20x-2600=0 equation:

x^2+20x-2600=0

a = 1; b = 20; c = -2600;
Δ = b2-4ac
Δ = 202-4·1·(-2600)
Δ = 10800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10800}=\sqrt{3600*3}=\sqrt{3600}*\sqrt{3}=60\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-60\sqrt{3}}{2*1}=\frac{-20-60\sqrt{3}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+60\sqrt{3}}{2*1}=\frac{-20+60\sqrt{3}}{2}
$